Question

Explain how you would use the
technique of completing the square to
solve the following:
X2 + 6x – 16 = 0

Answer 1

Answer:

two solutions

x1=-8 , x2=2

Step-by-step explanation:

x^{2}+6x-16=0 move constant to the right

x^{2}=6x=16 add ($\frac{6}{2} ^{2}$) to both sides of question

x^{2}+6x+($\frac{6}{2} ^{2}$)=16+($\frac{6}{2} ^{2}$)

x^{2}=6x+($\frac{6}{2} ^{2}$)=16+($\frac{6}{2} ^{2}$)

using a^{2}+2ab+b^{2}=(a+b)^{2}, factor the expression

$(x+\frac{6}{2} ^{2}=16+(\frac{6}{2})^{2}$

[tex](x+\frac{6}{2} ^{2}=25

reduce the fraction with 2

(x+3)^{2}=25

solve for x

the get final solution of x= -8 and x= 2