Respuesta :
Option B
12 over quantity x minus 7, x ≠ 7, x ≠ −3
Solution:
Given that we have to simplify quantity 12 x plus 36 over quantity x squared minus 4 x minus 21
So we have to simplify,
[tex]\frac{12x + 36}{ {x}^{2} - 4x - 21 }[/tex]
We have to find the restrictions on the variable
The above given Rational function is defined, for
[tex]{x}^{2} - 4x - 21\ne0\\\\(x+3)(x-7)\ne0\\\\x\ne -3,x\ne7[/tex]
In order to simplify the above expression, we need to factor both the numerator and the denominator
[tex]\rightarrow \frac{12x + 36}{ {x}^{2} - 4x - 21 } = \frac{12(x + 3)}{ {x}^{2} - 4x - 21}[/tex]
For the denominator, we need to split the middle term of the quadratic to get factored form,
[tex]\rightarrow \frac{12x + 36}{ {x}^{2} - 4x - 21 } = \frac{12(x + 3)}{ {x}^{2} - 7x + 3x- 21}[/tex]
[tex]\frac{12x + 36}{ {x}^{2} - 4x - 21 } = \frac{12(x + 3)}{ x(x - 7) + 3(x- 7)}[/tex]
Fcatoring the denominator part,
[tex]\frac{12x + 36}{ {x}^{2} - 4x - 21 } = \frac{12(x + 3)}{ (x + 3)(x - 7)}[/tex]
Cancel out common factors to get,
[tex]\frac{12x + 36}{ {x}^{2} - 4x - 21 } = \frac{12}{x - 7} \\\\where\\\\x\ne -3,x\ne7[/tex]
Thus option B is correct. 12 over quantity x minus 7, x ≠ 7, x ≠ −3