Question

"Professor Offenrokker has a solution that is 6.0 x 10-3 M of HCl of a solution. However, he needs 450 mL of a 6.0 x 10-4 M HCl solution. How much of the stock solution will he need to make the dilute solution?"

Answer 1

Answer : The volume of the stock solution he need to make the dilute solution will be, 45 mL

Explanation :

According to dilution dilution law:

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of concentrated solution

$M_2$ = molarity of dilute solution

$V_1$ = volume of concentrated solution

$V_2$ = volume of dilute solution

Given:

$M_1$ = $6.0\times 10^{-3}M$

$M_2$ = $6.0\times 10^{-4}M$

$V_1$ = ?

$V_2$ = 450 mL

Now put all the given values in the above formula, we get:

$(6.0\times 10^{-3}M)\times V_1=(6.0\times 10^{-4}M)\times 450mL$

$V_1=45mL$

Therefore, the volume of the stock solution he need to make the dilute solution will be, 45 mL