A set of 15 different integers has a median of 25 and a range of 25. What is the greatest possible integer that could be in this set?A. 32
B. 37
C. 40
D. 43
E. 50

Respuesta :

Answer:

Option D.

Step-by-step explanation:

It is given that a set of 15 different integers has a median of 25 and a range of 25.

Total number of integers is 15 which is an odd number.

[tex](\frac{n+1}{2}) th=(\frac{15+1}{2}) th=8th[/tex]

8th integers is median. It means 8th integers is 25.

7 different integers before 25 are 18, 19, 20, 21, 22, 23, 24.

It means the greatest possible minimum value is 18.

Range = Maximum - Minimum

25 = Maximum - 18

Add 18 on both sides.

25 +18 = Maximum

43 = Maximum

The greatest possible integer in the set is 43.

Therefore, the correct option is D.

Answer:

D. 43

Step-by-step explanation:

We have been given that a set of 15 different integers has a median of 25 and a range of 25.

Since each data point is different, so we can represent our data points as:

[tex]N_1,N_2,N_3,N_4,N_5,N_6,N_7,N_8, N_9,N_{10},N_{11},N_{12},N_{13},N_{14}, N_{15}[/tex]

Since there are 15 data points, this means that median will be 8th data point.

We have been given that median is 25, so [tex]n_8=25[/tex].

Since each data point is different, so 7 data points less than 25 would be:

18, 19, 20, 21, 22, 23, 24.

We know that range is the difference between upper value and lower value.

[tex]\text{Range}=\text{Upper value}-\text{Lower value}[/tex]

[tex]\text{Range}+\text{Lower value}=\text{Upper value}[/tex]

Upon substituting our given values, we will get:

[tex]25+18=\text{Upper value}[/tex]

[tex]43=\text{Upper value}[/tex]

Therefore, the greatest possible integer in this set could be 43 and option D is the correct choice.