Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2).

The equation of this circle is (x + )2 + (y + )2 =

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caylus
Hello,

C=(5,-4)
P=(-3,2)
|CP|²=(-3-5)²+(2+4)²=64+36=100

(x-5)²+(y+4)=100

Remember the  equation of the circle:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is its radio.

You already have the center, that is [tex](h,k)=(5,-4)[/tex] and hence we have

[tex]h=5[/tex] and [tex]k=-4[/tex] (be careful with the signs).

For the radio we use the formula of distance between two points:

[tex]r^2 = (-3-5)^2 + (2-(-4))^2= 64 + 36 = 100 = 10 ^2[/tex]

So the radio is 10.

Finally we replace tha data in the equation of the circle to obtain:

[tex](x-5)^2 + (y-(-4))^2=10^2\\\\(x-5)^2 + (y+4)^2=10^2[/tex]

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