Respuesta :

Answer:

Given expression [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex] is equivalent to the expression [tex]2(4x-3)[/tex].

Step-by-step explanation:

Given expression is  [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex]

To simplify the expression:

[tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})=\frac{18x-12}{3}+\frac{4x-4}{2}[/tex]

Taking LCM 6 to the above expression we get

[tex]=\frac{(18x-12)2+3(4x-4)}{6}[/tex] (Applying multiplication rules)

[tex]=\frac{36x-24+12x-12}{6}[/tex]  ( doing sums to the terms)

[tex]=\frac{48x-36}{6}[/tex]

[tex]=8x-6[/tex]

We can take common number 2 outside to the above expression

[tex]=2(4x-3)[/tex]

Therefore  [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})=2(4x-3)[/tex]

Therefore given expression [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex] is equivalent to the expression [tex]2(4x-3)[/tex].