Answer:
Given expression [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex] is equivalent to the expression [tex]2(4x-3)[/tex].
Step-by-step explanation:
Given expression is [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex]
To simplify the expression:
[tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})=\frac{18x-12}{3}+\frac{4x-4}{2}[/tex]
Taking LCM 6 to the above expression we get
[tex]=\frac{(18x-12)2+3(4x-4)}{6}[/tex] (Applying multiplication rules)
[tex]=\frac{36x-24+12x-12}{6}[/tex] ( doing sums to the terms)
[tex]=\frac{48x-36}{6}[/tex]
[tex]=8x-6[/tex]
We can take common number 2 outside to the above expression
[tex]=2(4x-3)[/tex]
Therefore [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})=2(4x-3)[/tex]
Therefore given expression [tex]\frac{2}{3}(9x-6)+4(\frac{1}{2}x-\frac{1}{2})[/tex] is equivalent to the expression [tex]2(4x-3)[/tex].