Answer:
Outer perimeter of the resulting 2-dimensional shape will be 18.84 units
Step-by-step explanation:
From the figure, we could see
AE = FB = 1
And minor arc EF
=> [tex]\frac{2 \pi (1) }{6}[/tex]
=>[tex]= \frac{2 \pi}{ 6}[/tex]
=>[tex]= \frac{ \pi}{ 3}[/tex]
So by symmetry the perimeter is
=>[tex]3(2 + \frac { \pi}{3} )[/tex]
=>[tex]3(\frac {6 \pi}{3} )[/tex]
=>[tex]6 \pi[/tex]
=> [tex]6 \times 3.14[/tex]
=> 18.84 units
