Answer: [tex]x=\dfrac{25}{3}[/tex]
Step-by-step explanation:
The given equation : [tex]\log_2(3x+7)=5[/tex]
Using logarithmic property : [tex]\log_a N=M\to N=a^M[/tex]
The given equation will be equivalent to [tex](3x+7)=2^5[/tex]
[tex]\Rightarrow\ 3x+7=32[/tex]
Subtract 7 from both sides , we get
[tex]3x=25[/tex]
Divide both sides by 3 , we get
[tex]x=\dfrac{25}{3}[/tex]
Hence, the solution is [tex]x=\dfrac{25}{3}[/tex]