Create a FLOWCHART and a PSEUDOCODE for each problem.

Use the information below to create a pseudocode (which can be a text-based description for solving the problems) and a flowchart (using flowchart symbols to illustrate how you would program) to solve each problem. You may use Microsoft Word® for your pseudocode and Microsoft PowerPoint® for your flowchart.

1. Problem 1: Write a program that will calculate the problem and stop after the condition has been met. This is an IF/THEN/ELSE problem.

a=1

b=a+1

c=a+b

Condition: If c is less than 5, then the loop will continue; else, it will end.

2. How many loops will be necessary to meet the condition incrementing 'c' by 1? Why?

Provide a correct response to "How many loops will be necessary to meet the condition incrementing 'c' by 1? Why?"

In the question the condition increment 'c' by 1 seems to be a typo. and it should be 'a' by 1. If we increment c by 1 each loop, it does nothing because c is will be set again by the calculation of c = a + b.

IF the condition is increment c by 1 then the answer is that no amount of loops will have c meet the condition as it resets each loop.

For the condition increment a by 1 the answer is that it will take two loops. First loop c has 3 and in the second loop if it is according to incrementing by 1, c is 5. When c is 5 this means that the condition c<5 becomes false as c gets equal to 5. So the program will end after this i.e after 2nd loop.

Lets understand this

At first a=1, b=a+1=1+1=2, so b=2, c=a+b so c=1+2 c=3
At second a is incremented by 1, so it becomes a=2, b=a+1 so b=2+1 so b=3, c=a+b which means c=2+3 so c=5
Program ends after two loops as the condition has been met.

Above pseudo code can be modified for 2 as

PSEUDOCODE1

initialize a to 1

b = a+1

c = a + b

If c is less than 5

start from the beginning (and increment a)

else

stop the program

print a

Flowchart 2 is attached

For the condition incrementing c by 1

PSEUDOCODE

a=1

b=a+1

c=a+b

while c is less than 5:

increment c by 1

END while

display c

Flowchart 3 is attached

Number of loops here will be 5. This is explained below:

first iteration: a=1, b=2, c=3
c<5 so c is incremented by 1. This means c becomes 4 (c=3+1)
condition c<5 is again true, so c is incremented by 1 again, This means value of c becomes 5 (c=4+1).
The loop breaks as the condition c<5 gets false because now the value of c=5. This value is displayed.
So 5 loops will be necessary to meet this condition.