Respuesta :
a) 12.95*10^20 molecules
b) 5.84*10^20 molecules
Explanation:
a)Tylenol
Mass of Tylenol = 325 mg
(m)=325*10^-3 g
Molecular weight of Tylenol(M) = 151.16256 g/mol
the number of moles present
n = m/M
= 325*10^-3 g /151.1656 g/mol
= 2.15 *10^-3 mol
the number of molecules present
N= nNa
=(2.15*10^ -3 mol)(6.023*10^23 molecules/mol)
N=12.95*10 ^20 molecules
b)Advil
Mass of Advil = 200 mg
m=200*10^-3 g
Molecular weight of Advil(M) =206.28082 g/mol
the number of moles
n=m/M
=200*10^ -3 g/ 206.28082 g/mol
=0.96955*10^ -3 mol
the number of molecules resent
N=nNa
=(0.96955*10^ -3)(6.023*10^ 23 molecules/ mol)
N=5.84*10^20 molecules
Tylenol contains more molecules of active ingredient hence it is a more effective drug.
We have to find the number of molecules in each of the drugs. In the drug, tylenol, the molar mass of the compound C8H9NO2 is;
8(12) + 9(1) + 14 + 2(16) = 96 + 9 + 14 + 32 =151 g/mol
Number of moles = 325 × 10^-3 g/151 g/mol = 0.0022 moles
1 mole contains 6.02 × 10^23 molecules
0.0022 moles contains 0.0022 moles × 6.02 × 10^23 molecules /1 mole = 1.32 × 10^21 molecules
For Advil;
Molecular mass= 13(12) + 18(1) + 2(16) = 156 + 18 + 32 = 206 g/mol
Number of moles = 0.2 g/ 206 g/mol = 0.00097 moles
1 mole contains 6.02 × 10^23 molecules of advil
0.00097 moles contains 0.00097 moles × 6.02 × 10^23 molecules /1 mole = 5.8 × 10^20
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