What is the common difference of an AP which has its first term as 100 and the sum of its first 6 terms = 5 times the sum of its next six terms Pick one of the choices 1. 10 2. -10 3. 12 4. 15

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Answer:

The common difference of given AP is Option 2) -10.

Step-by-step explanation:

We are given the following information in the question:

First term of AP, a  = 100

The sum of its first 6 terms = 5(the sum of its next six terms)

We have to find the common difference of AP.

The sum of n terms of AP is given by:

[tex]S_n = \dfrac{n}{2}\big(2a + (n-1)d\big)[/tex]

where a is the first term and d is the common difference.

Thus, we can write:

[tex]S_6 = 5 (S_{12}-S_6)\\\dfrac{6}{2}\big(200 + (6-1)d\big) = 5\bigg(\dfrac{12}{2}\big(200 + (12-1)d\big)-\dfrac{6}{2}\big(200 + (6-1)d\big)\bigg)\\\\600 + 15d =5(1200+66d-600-15d)\\600+15d=3000+255d\\2400 = -240d\\d = -10[/tex]

Thus, the common difference of given AP is -10.