Question

A spring has a spring constant of 115 N/m. How much energy is stored in the
spring when it is compressed 0.15 m past its natural length?
O A. 1.33
OB. 0.82
O C. 17.30
O D. 8.6J

Answer 1

Explanation:

Elastic energy stored in a spring is:

EE = ½ kx²

EE = ½ (115 N/m) (0.15 m)²

EE = 1.3 J

Answer 2

Answer: The energy stored in the spring is 1.33 J

Explanation:

To calculate the energy stored in the spring, we use the equation:

$E=\frac{1}{2}kx^2$

where,

E = energy stored in the spring

k = spring constant = 115 N/m

x = compression of the spring = 0.15 m

Putting values in above equation, we get:

$E=\frac{1}{2}\times 115\times (0.15)^2\\\\E=1.33J$

Hence, the energy stored in the spring is 1.33 J