Question

What is an equation of the line that passes through the point (-2, 1) and is parallel to the line whose equation is 4x-2y=8?

Answer 1

Answer:

y-1=2(x+2)

Step-by-step explanation:

4x-2y=8

2y=4x-8

y=4/2x-8/2

y=2x-4

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Parallel means same slope.

m=2

y-y1=m(x-x1)

y-1=2(x-(-2))

y-1=2(x+2)

Answer 2

Parallel lines have the same slope

The equation of the line is: $y = 2x+5$

The equation is given as:

$4x - 2y =8$

Divide through by 2

$2x - y =4$

Make y the subject

$y = 2x - 4$

Because the required equation and $y = 2x - 4$ are parallel, then they must have the same slope

A linear equation is represented as:

$y = mx + c$

Where:

$m = slope$

So, by comparison

$m = 2$

This means that the slope of the required line is 2

The equation is then calculated as:

$y = m(x - x_1) + y_1$

So, we have:

$y = 2(x--2) + 1$

$y = 2(x+2) + 1$

Open brackets

$y = 2x+4 + 1$

$y = 2x+5$

Hence, the equation of the line is: $y = 2x+5$

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