Respuesta :

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) [tex]b^2=a^2+c^2-2(a)(c)cos(B)[/tex]  

Part 3) [tex]b=11.6\ in[/tex]

Step-by-step explanation:

we have

In the triangle ABC

[tex]a=11\ in\\c=9\ in\\B=70^o[/tex]

Part 1) Which information about the triangle is given?

In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)

see the attached figure to better understand the problem

Part 2) Which formula can you use ti find b?

I can use the law of cosines

[tex]b^2=a^2+c^2-2(a)(c)cos(B)[/tex]  

we have

[tex]a=11\ in\\c=9\ in\\B=70^o[/tex]

substitute the given values

[tex]b^2=11^2+9^2-2(11)(9)cos(70^o)[/tex]

[tex]b^2=202-67.72[/tex]  

[tex]b=11.59\ in[/tex]

Part 3) What is b, rounded to the nearest tenth?

Remember that

To Round a number

a) Decide which is the last digit to keep  

b) Leave it the same if the next digit is less than [tex]5[/tex] (this is called rounding down)  

c) But increase it by  [tex]1[/tex] if the next digit is  [tex]5[/tex] or more (this is called rounding up)

In this problem we have

[tex]11.59\ in[/tex]

We want to keep the digit [tex]5[/tex]

The next digit is [tex]9[/tex] which is 5 or more, so increase the "5" by 1 to "6"

therefore

[tex]b=11.6\ in[/tex]

Ver imagen calculista

Answer:

Question 1:

SAS

Question 2:

[tex]b^{2} =a^{2} +c^{2} -2ac * cos(B)[/tex]

Question 3:

11.6 in

Step-by-step explanation:

Edg2020