Respuesta :
Answer:
Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)
Part 2) [tex]b^2=a^2+c^2-2(a)(c)cos(B)[/tex]
Part 3) [tex]b=11.6\ in[/tex]
Step-by-step explanation:
we have
In the triangle ABC
[tex]a=11\ in\\c=9\ in\\B=70^o[/tex]
Part 1) Which information about the triangle is given?
In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)
see the attached figure to better understand the problem
Part 2) Which formula can you use ti find b?
I can use the law of cosines
[tex]b^2=a^2+c^2-2(a)(c)cos(B)[/tex]
we have
[tex]a=11\ in\\c=9\ in\\B=70^o[/tex]
substitute the given values
[tex]b^2=11^2+9^2-2(11)(9)cos(70^o)[/tex]
[tex]b^2=202-67.72[/tex]
[tex]b=11.59\ in[/tex]
Part 3) What is b, rounded to the nearest tenth?
Remember that
To Round a number
a) Decide which is the last digit to keep
b) Leave it the same if the next digit is less than [tex]5[/tex] (this is called rounding down)
c) But increase it by [tex]1[/tex] if the next digit is [tex]5[/tex] or more (this is called rounding up)
In this problem we have
[tex]11.59\ in[/tex]
We want to keep the digit [tex]5[/tex]
The next digit is [tex]9[/tex] which is 5 or more, so increase the "5" by 1 to "6"
therefore
[tex]b=11.6\ in[/tex]
Answer:
Question 1:
SAS
Question 2:
[tex]b^{2} =a^{2} +c^{2} -2ac * cos(B)[/tex]
Question 3:
11.6 in
Step-by-step explanation:
Edg2020