Answer:
The Acceleration of bike after 3 minutes of ride is 14 meter² per minutes
Step-by-step explanation:
Given as :
The displacement of bike is the function of time
i.e s(t) = t³ - 2 t² + 3 meters
The Time of bike acceleration = t = 3 minutes
Let The Acceleration of bike = a meter² per minutes
Now, According to question
∵ Acceleration is define as the rate of change of velocity
i.e acceleration = [tex]\dfrac{\textrm velocity}{\textrm time}[/tex]
or, a = [tex]\dfrac{\textrm v}{\textrm t}[/tex]
And
Velocity is define as rate of change of displacement
i.e velocity = [tex]\dfrac{\textrm displacement}{\textrm time}[/tex]
Or, v = [tex]\dfrac{\textrm s}{\textrm t}[/tex]
Since here displacement is function of time
So , v = [tex]\frac{\partial s(t)}{\partial t}[/tex]
Or, v = [tex]\frac{\partial (t³ - 2 t² + 3)}{\partial t}[/tex]
Or, v = 3 t² - 4 t + 3
So, velocity is the function of time = v = 3 t² - 4 t + 3 meter per minutes
Now, Again
Acceleration = a = [tex]\frac{\partial v}{\partial t}[/tex]
Or, a = [tex]\frac{\partial (3 t² - 4 t + 3)}{\partial t}[/tex]
Or, a = 6 t - 4
∴ Acceleration is the function of time = a = 6 t - 4
Now, Acceleration of bike after 3 minutes
So, at t = 3 min
i.e a = 6 t - 4
Or, a = 6 × 3 - 4
Or, a = 18 - 4
∴ a = 14 meter² per minutes
Hence, The Acceleration of bike after 3 minutes of ride is 14 meter² per minutes . Answer