The power of the light emitted is 3.6 W
Explanation:
The efficiency of an electric device is defined as follows:
[tex]\eta=\frac{P_{out}}{P_{in}}[/tex]
where
[tex]P_{out}[/tex] is the output power
[tex]P_{in}[/tex] is the input power
For the LED in this problem, we have
[tex]P_{in}=4W[/tex] is the power in input
[tex]\eta=0.90[/tex] is the efficiency of the LED
Re-arranging the equation and substituting the numbers, we can find the power output, which is the power of the light emitted:
[tex]P_{out}=\eta P_{in}=(0.90)(4)=3.6W[/tex]
Learn more about power:
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