Answer:
Option C . 5.3 in
Step-by-step explanation:
The complete question is
An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles
Let
x ----> the length of the art project in inches
y ----> the width of the art project in inches
we know that
The area of the rectangular art project is equal to
[tex]A=xy[/tex]
we have
[tex]A=63.6\ in^2[/tex]
so
[tex]63.6=xy[/tex] ----> equation A
[tex]x=10+2=12\ in[/tex]
substitute the value of x in the equation A
[tex]63.6=(12)y[/tex]
solve for y
[tex]y=63.6/12\\y=5.3\ in[/tex]
