What is the equation for the hyperbola shown?

A. x²/8² - y²/5² = 1

B. x²/5² - y²/8² = 1

C. y²/8² - x²/5² = 1

D. y²/5² - x²/8² = 1

What is the equation for the hyperbola shown A x8 y5 1 B x5 y8 1 C y8 x5 1 D y5 x8 1 class=

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Answer:

D. y²/5² - x²/8² = 1

Step-by-step explanation:

A and B are both incorrectly oriented, and D is the only hyperbola that contains the points (0,5) and (0,-5).

Verification (0,5) and (0,-5) are in the hyperbola:

First replace x and y with corresponding x and y values (We will start with x=0 and y=5)

[tex]\frac{5^{2}}{5^{2}}-\frac{0^{2}}{8^{2}}=1[/tex]

Then simplify.

[tex]\frac{25}{25}-\frac{0}{16}=1[/tex]

[tex]1-0=1[/tex]

[tex]1=1[/tex]

If the result is an equation (where both sides are equal to each other) then the original x and y values inputted are valid. The same is true with x and y inputs x=0 and y=-5, or any other point along   the hyperbola.

Answer:

D. y²/5² - x²/8² = 1

Step-by-step explanation:

From the graph of the hyperbola, we can see that points (0,5) and (0,-5) form part of the hyperbola.

This means that the equation of the hyperbola should be satisfied by these points.

Substituting x=0 and y=5 in the given options:

A. LHS = -1 while RHS = 1

B. LHS = [tex]\[\frac{-5^{2}}{8^{2}}\][/tex] while RHS = 1

C. LHS = [tex]\[\frac{5^{2}}{8^{2}}\][/tex] while RHS = 1

D. LHS = 1 and RHS = 1

So only option D contains the point (0,5).

Now verifying option D for the point (0,-5):

LHS = 1 and RHS = 1

So equation D is the correct equation for the hyperbola.

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