Answer:
It will take 19.044 sec for 0.15 mol of Cl2 to effuse under the same conditions
Explanation:
From Graham's law of effusion, R1/R2 = √(M2/M1)
Since the number of moles is the same,
t2/t1 = √((M2/M1)
t1 (time taken for I2 to effuse) = 36 sec, M2 (molecular weight of Cl2)= 2×35.5 = 71, M1 (Molecular weight of I2) = 2×126.9 = 253.8
t2/36 = √(71/253.8)
t2/36 = 0.529
t2 = 36 × 0.529 = 19.044 sec
Answer:
It will take 19.03 seconds to effuse Cl2
Explanation:
Step 1: Data given
0.15 mol of I2 effuses in 36 sec
Step 2: Calculate the time to effuse 0.15 mol of Cl2
R2/R1 = √(M1/M2)
R = 1/T
T1/T2 = √(M1/M2)
⇒ with T1 = the time needed to effuse I2 = 36 sec
⇒ with T2 = the time needed to effuse Cl2 = TO BE DETERMINED
⇒ with M1 = the molar mass of I2 = 253.8 g/mol
⇒ with M2 = the molar mass of Cl2 = 70.9 g/mol
36/X = √(253.8/70.9)
X= 19.03
It will take 19.03 seconds to effuse Cl2
