Question

A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m twice every second, what is the tension in the string

Answer 1

Answer:

T = 19.75 N

Explanation:

given,

mass of ball = 0.25 Kg

radius = 0.5 m

frequency = 2 s⁻¹

tension in the string = ?

angular velocity

ω = 2 π f

ω = 2 π x 2

ω = 12.57 rad/s

tension on the string is equal to the centripetal force

T = m ω² r

T = 0.25 x 12.57² x 0.5

T = 19.75 N

Tension in the string is equal to T = 19.75 N

Answer 2

The tension in the string when the ball rotates in a horizontal circle is 19.74 N.

Tension in the string

The tension in the string when the ball rotates in a horizontal circle is calculated using the following equations;

T = Fc

where;

• Fc is centripetal force

T = ma

T = m (ω²r)

T = m(2πf)²r

T = 0.25 x (2π x 2)² x 0.5

T = 19.74 N

Thus, the tension in the string when the ball rotates in a horizontal circle is 19.74 N.

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