This is a incomplete question.The complete question is:
A chemist adds 180.0 ml of a 1.77 mol/L of sodium thiosulfate solution to a reaction flask. Calculate the mass in grams of sodium thiosulfate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.
Answer: 50.4 g
Explanation:
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}[/tex] .....(1)
Molarity of sodium thiosulfate solution = 1.77 M
Volume of sodium thiosulfate solution = 180.0 mL = 0.1800 L
Putting values in equation 1, we get:
[tex]\text{Moles of sodium thiosulfate}={1.77}\times{0.1800}=0.319moles[/tex]
Mass of sodium thiosulfate = [tex]moles\times {\text {Molar mass}}=0.319moles\times 158.11g/mol=50.4g[/tex]
Thus 50.4 g of sodium thiosulfate the chemist has added to the flask.
