Question

Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)

Answer 1

Answer:

$=\frac{17}{3}$

Step-by-step explanation:

Density of a function is $\rho(x,y)=x^{2} +y^{2}$

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

$\frac{y}{4} =\frac{x-1}{-1}$

$y=4-4x$

=$\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$

=$\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$  

=$\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

=$\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3}  )dx$

=$=(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})$  

$=\frac{17}{3}$