Answer:
Step-by-step explanation:
[tex]\dfrac{a^3b^6}{a^2b^3}-a^4b^2\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=a^{3-2}b^{6-3}-a^4b^2=a^1b^3-a^4b^2[/tex]
[tex]\text{If is}\\\\\dfrac{a^3b^6}{a^2b^3-a^4b^2}\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=\dfrac{a^3b^6}{a^2b^2(b-a^2)}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\dfrac{a^{3-2}b^{6-2}}{b-a^2}\\\\=\dfrac{a^1b^4}{b-a^2}[/tex]
