Respuesta :

gmany

Answer:

[tex]\large\boxed{\dfrac{8g^6}{23h^3}}[/tex]

Step-by-step explanation:

[tex]\dfrac{\frac{h}{23g^2}}{\frac{h^4}{8g^8}}=\dfrac{h}{23g^2}:\dfrac{h^4}{8g^8}=\dfrac{h}{23g^2}\cdot\dfrac{8g^8}{h^4}\\\\=\dfrac{8}{23}\cdot\dfrac{h}{h^4}\cdot\dfrac{g^8}{g^2}\\\\=\dfrac{8}{23}\cdot\dfrac{h\!\!\!\!\diagup}{h^{4\!\!\!\!\diagup^3}}\cdot\dfrac{g^{8\!\!\!\!\diagup^6}}{g^{2\!\!\!\!\diagup^1}}\\\\=\dfrac{8}{23}\cdot\dfrac{1}{h^3}\cdot\dfrac{g^6}{1}\\\\=\dfrac{8g^6}{23h^3}[/tex]

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