Respuesta :
Answer:
(C) 1/6
Step-by-step explanation:
Pr that event A will occur = 0.5
Pr that event B will occur = 0.6
Pr that both A and B occurs = 0.1
Pr(A) = 0.5
Pr(B)= 0.6
Pr(AnB) = 0.1
The conditional probability of A given B is Pr (A|B) = Pr(AnB) / Pr(A)
= 0.1/0.6
= 1/6 (C)
The conditional probability of A, given B is [tex]P(A|B)=\dfrac{1}{6}[/tex]
The Probability of occurring event A is [tex]0.5[/tex]
The Probability of occurring event B is [tex]0.6[/tex]
The Probability of occurring both events A and B is [tex]0.1[/tex].
Substitute the value of the parameters [tex]P(A\cap B)[/tex] and [tex]P(B)[/tex] in the formula [tex]P(A|B)=\dfrac{P(A\cap B}{P(B)}[/tex] to get the conditional probabilty of A, given B as-
[tex]\begin{aligned}P(A|B)&=\dfrac{P(A\cap B}{P(B)}\\P(A|B)&=\dfrac{P(0.1}{0.6}\\P(A|B)&=\dfrac{1}{6}\end{aligned}[/tex]
So, the conditional probability of A, given B is [tex]P(A|B)=\dfrac{1}{6}[/tex]
Learn more about conditional probability here:
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