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Answer:

The answer is D. mark me brainliest plz.

Step-by-step explanation:

Happy New Years

gmany

Answer:

[tex]\large\boxed{D.\ \dfrac{practice\cdot days}{distractions^2}}[/tex]

Step-by-step explanation:

[tex]S=\dfrac{P\cdot t}{D^2}\\\\P\to practice\\t\to days\\D\to distractions\\\\S=\dfrac{P\cdot t}{D^2}\ \bigg(\dfrac{practice\cdot days}{distractions^2}\bigg)[/tex]

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