In ΔADC≅ΔBDC the corresponding sides are AC=BC, AD=BD. The corresponding angles are ∠A=∠B =45°.
Step-by-step explanation:
Consider ΔADC:
The angle of D ( ∠D) = 90°.
Then other angles( ∠A & ∠C) in ΔADC = 45°.
(Since sum of the angles of the triangle is always 180°.)
The ΔBDC is the mirror transformation of ΔADC.
∴ ∠A and∠B are the corresponding angles with 45°.
Since ∠C and ∠D is same in both the triangles with 45° and 90°.
And AC=BC, AD=BD are the corresponding sides.
Since CD is same in both the triangles.