Respuesta :

In ΔADC≅ΔBDC the corresponding sides are AC=BC, AD=BD. The corresponding angles are ∠A=∠B =45°.

Step-by-step explanation:

Consider ΔADC:

The angle of D ( ∠D) = 90°.

Then other angles( ∠A & ∠C) in ΔADC = 45°.

(Since sum of the angles of the triangle is always 180°.)

The ΔBDC is the mirror transformation of ΔADC.

∠A and∠B are the corresponding angles with 45°.

Since ∠C and ∠D is same in both the triangles with 45° and 90°.

And AC=BC, AD=BD are the corresponding sides.

Since CD is same in both the triangles.

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