Answer:
Yes, we can conclude that more than 70% of the households in this city have high speed internet access
Step-by-step explanation:
given that in a sample of 150 households in a certain city, 110 had high-speed internet access.
Sample proportion = [tex]\frac{110}{150} \\=0.7333[/tex]
Hypothetical proportion is 0.70
Hence std error of p = [tex]\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.7*0.3}{150} } \\=0.03742[/tex]
[tex]H_0: p = 0.7\\H_a: p \neq 0.7[/tex]
(two tailed test at 5% level)
p difference = 0.0333
Test statistic Z = p diff/std error = 0.891
p value = 0.379
since p value is >0.05, we accept H0
Yes, we can conclude that more than 70% of the households in this city have high speed internet access