Question

Please help mee pleaseee

Answer 1

Answer:

The exact answer in terms of radicals is $x = 5*\sqrt[3]{25}$

The approximate answer is $x \approx 14.62009$ (accurate to 5 decimal places)

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Work Shown:

Let $y = \sqrt[5]{x^3}$

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

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Since $y = \sqrt[5]{x^3}$ and y = 5, this means we can equate the two expressions and solve for x

$y = 5$

$\sqrt[5]{x^3} = 5$

$x^3 = 5^5$ Raise both sides to the 5th power

$x^3 = 3125$

$x = \sqrt[3]{3125}$ Apply cube root to both sides

$x = \sqrt[3]{125*25}$

$x = \sqrt[3]{125}*\sqrt[3]{25}$

$x = \sqrt[3]{5^3}*\sqrt[3]{25}$

$x = 5*\sqrt[3]{25}$

$x \approx 14.62009$

Answer 2

Answer:

x = 14.62 (Rounding to two decimal places)

Step-by-step explanation:

Let's solve for x, this way:

- 7 = 8 - 3 ⁵√x³

- 15 = - 3 ⁵√x³ (Subtracting 8 at both sides)

5 =  ⁵√x³ (Dividing by - 3 at both sides)

5 ⁵ = x³(Raising both sides to the 5th power)

3,125 = x³

x = ∛ 3,125 (Cube root to both sides)

x = 14.62 (Rounding to two decimal places)