Answer:
The thermal Energy absorbed each hour = 750420 kJ
Explanation:
Efficiency of a Carnot engine = W/Q = (Th-Tc)/Th ............... Equation 1.
W/Q = (Th-Tc)/Th
making Q the subject of the equation above,
Q = W(Th)/(Th-Tc)........................ Equation 2
Where Q = input power, W = output power, Th = temperature of the hot reservoir, Tc = Temperature of the cold reservoir.
Given: W= 148 kW, Th = 727 °C = 727 + 273 = 1000 K, Tc = 17 °C =17 + 273 = 290 K.
Substituting these values into equation 2,
Q = 148(1000)/(1000-290)
Q = 148000/710
Q = 208.45 kw
The thermal Energy absorbed each hour = 208.45 kW × 3600 s
The thermal Energy absorbed each hour = 750420 kJ
