Question

A rain cloud contains 2.66 x 10^7 kg of water vapor. How long would it take for a 2.00 kW pump to raise the same amount of water to the cloud's altitude, 2.00 km.

Answer 1

Answer:

It will take 0.72*10^8 hours

Explanation:

Potential energy formula is:

$P_{E}=m*g*h$

Where:

m=2.66*10^7 kg

g=9.8 m/s^2

h = 2000 m

$P_{E}=2.66*10^7*9.8*2000=5.21*10^{11}$

Potential energy of the water vapor is 5.21*10^11 Joule

When it converted to watt/hour  it becomes 1.45*10^8 Watt/hour.

When its divide by 2 because of 2 kW pump is going to be used. It will take 0.72*10^8 hours