Answer:
We need 27.7 grams of HCl to produce 48.2 grams of FeCL2
Explanation:
Step 1: Data given
Mass of FeCl2 produced = 48.2 grams
Molar mass of FeCl2 = 126.75 g/mol
Step 2: The balanced equation
Fe (s) + 2 HCl (aq) → FeCl2 (aq) + H2 (g)
Step 3: Calculate moles of FeCl2
Moles FeCl2 = mass FeCl2 / molar mass FeCl2
Moles FeCl2 = 48.2 grams / 126.75 g/mol
Moles FeCl2 = 0.380 moles
Step 4: Calculate moles of HCl
For 1 mol of Fe we need 2 moles of HCl to produce 1 mol of FeCl2
For 0.380 moles of FeCl2 we need 2*0.380 moles of HCl = 0.760 moles of HCl
Step 5: Calculate mass of HCl
Mass of HCl = moles HCl * molar mass of HCl
Mass of HCl : 0.760 moles * 36.46 g/mol
Mass of HCl = 27.7 grams
We need 27.7 grams of HCl to produce 48.2 grams of FeCL2
