Answer:
The energy involved in melting 120 g of ice = 40080 J
Explanation:
Heat of fusion of water: Heat of fusion is the heat Energy required to convert a substance from solid to its liquid form without a change in energy.
The S.I unit of heat of fusion is J/kg.
Q = lm............ equation 1
Where Q = Energy involved in melting the ice, l = heat of fusion of water, m = mass of water.
Given: l = 0.334 kJ/g, m = 120 g
Substituting these values into equation 1
Q = 0.334×120
Q = 40.08 kJ
Q = 40080 J
Therefore the energy involved in melting 120 g of ice = 40080 J
