Respuesta :
Answer: [tex]y=-40x+300[/tex]
Step-by-step explanation:
This car follows a line, hence its motion can be modeled by the Line equation.
In fact, we already have two points of the line, if we call [tex]x[/tex] the time in hours and [tex]y[/tex] the traveled distance in miles:
Point 1: [tex](x_{1},y_{1})=(0,300)[/tex]
Since we are told the car's initial position is 300 miles in the time 0 h
Point 2: [tex](x_{2},y_{2})=(3,180)[/tex]
Since we are told the car's final position is 180 miles after 3h
Let's find the Slope [tex]m[/tex]:
[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]m=-40[/tex] This is the slope of the line
Now, the equation of the line is:
[tex]y=mx+b[/tex]
We already know the slope, now we have to find the intersection point with the y-axis ([tex]b[/tex]) with any of the given points. Let's choose Point 1: [tex](x_{1},y_{1})=(0,300)[/tex]
[tex]300=-40(0)+b[/tex]
Isolating [tex]b[/tex]:
[tex]b=-300[/tex]
Then, the equation of the line is:
[tex]y=-40 x+300[/tex]