Answer:
Step-by-step explanation:
given that the characteristic polynomial of a 5x5 matrix is given below.
[tex]\lambda ^5-11\lambda ^4+18\lambda ^3[/tex]
The solution is simple
Equate the above 5th degree polynomial in lambda to 0 and solve for lambda
We would have 5 solutions
Equating to 0 and factorising we get
[tex]=\lambda ^3(\lambda ^2-11\lambda +18)\\= \lambda ^3(\lambda -9)(\lambda -2)=0[/tex]
Equate each factor to 0
Since lambda has power 3 , we say that 0 is a root with multiplicity 3
(this means 3 times same value repeated as root)
Other roots are 9 and 1 with multiplicity 1 each.