Answer:
The distance covered by the cart is 2.25 meters.
Explanation:
It is given that,
Mass of the cart, m = 30 kg
Horizontal force, F = 15 N
Let d is the distance covered by the cart in 3 seconds if it started from rest. If a is the acceleration of the cart. Using second law of motion as :
[tex]F=ma[/tex]
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{15\ N}{30\ kg}[/tex]
[tex]a=0.5\ m/s^2[/tex]
The distance covered by the cart is given by :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0
[tex]d=\dfrac{1}{2}\times 0.5\times (3)^2[/tex]
d = 2.25 meters
So, the distance covered by the cart is 2.25 meters. Hence, this is the required solution.