Answer:
57.94415 kJ
Explanation:
[tex]T_h[/tex] = Environment temperature = 300 K
[tex]T_c[/tex] = Brick temperature = 150 K
C = Specific heat of brick = 1 kJ/K
Work done is given by
[tex]W=\int_{T_c}^{T_h}C(1-\dfrac{T_h}{T})\\\Rightarrow W=C(T_h-T_c)-T_hCln\dfrac{T_h}{T_c}\\\Rightarrow W=1(300-150)-300\times 1ln\dfrac{300}{150}\\\Rightarrow W=-57.94415\ kJ[/tex]
The work performed is 57.94415 kJ