Question

A coil with magnetic moment 1.48 Aâ‹…m2 is oriented initially with its magnetic moment antiparallel to a uniform magnetic field of magnitude 0.805 T .What is the change in potential energy of the coil when it is rotated 180 degrees, so that its magnetic moment is parallel to the field? Express the answer in joules.

Answer 1

Answer:

-2.3828 J

Explanation:

Magnetic moment = 1.48 Am²

B = Magnetic field = 0.805 T

$\theta_i$ = Initial turns = 180°

$\theta_f$ = Final turns = 360°

Initial in potential energy

$U_i=-mBcos\theta_i\\\Rightarrow U_i=-1.48\times 0.805\times cos180\\\Rightarrow U_i=1.1914\ J$

Final in potential energy

$U_f=-mBcos\theta_f\\\Rightarrow U_f=-1.48\times 0.805\times cos360\\\Rightarrow U_f=-1.1914\ J$

Change potential energy would be

$\Delta U=U_f-U_i\\\Rightarrow \Delta U=-1.1914-1.1914\\\Rightarrow \Delta U=-2.3828\ J$

Change in potential energy is -2.3828 J

Answer 2

The change potential energy is mathematically given as

dU=-2.3828J

What is the Change potential energy?

Question Parameters:

A coil with magnetic moment 1.48 Aâ‹…m2

the magnetic field of magnitude 0.805 T

the change in potential energy of the coil when it is rotated 180 degrees

Generally, the equation for the Initial in potential energy  is mathematically given as

U_i=-mBcos\theta

Therefore

U_i=-1.48* 0.805* cos180

U_i=1.1914J

For the Final potential energy

U_f=-mBcos\theta

U_f=-1.48* 0.805*cos360

U_f=-1.1914 J

In conclusion, The Change potential energy is

d U=-1.1914-1.1914

dU=-2.3828J

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