Answer:
102.95652 N
Explanation:
[tex]F_1[/tex] = Force on muscle = 222 N
[tex]F_2[/tex] = Force on incisor
[tex]r_1[/tex] = Distance of muscle = 3.2 cm
[tex]r_2[/tex] = Distance to incisor = 6.9 cm
Here the torque in the system is conserved so we have
[tex]F_1r_1=F_2r_2\\\Rightarrow F_2=\dfrac{F_1r_1}{r_2}\\\Rightarrow F_2=\dfrac{222\times 3.2}{6.9}\\\Rightarrow F_2=102.95652\ N[/tex]
The force the incisors exert is 102.95652 N