Answer: False
Step-by-step explanation:
Given : A clothing manufacturer knows that the average amount of button flaws (broken, incorrect, or missing) for a particular shirt is 2.
Then, the average number of flaws in 48 shirts = 2 x 48 =96
let x denotes the number of flaws.
Formula for Poisson probability model = [tex]P(X= x)=\dfrac{e^{-\mu}\mu^x}{x!}[/tex]
, where [tex]\mu[/tex] = Average.
Now , the probability that the inspector finds no button flaws is
[tex]P(X= x)=\dfrac{e^{-96}(96)^0}{0!}\\\\=e^{-96}\approx0\neq0.0366[/tex]
Thus , the given statement is False.