Answer:
The force applied to the smaller piston = 2512 N
Explanation:
Hydraulic press: A hydraulic press is a device used to produce a very large force. A hydraulic force operates based on pascal's principle.
F/f = A/a................ Equation 1
making f the subject of the equation above
f =(F×a)/A............. Equation 2
Where F = Force on the larger piston, f = force on the smaller piston, A = area of the larger piston, a = area of the smaller piston.
Given: F = 3200 N, and
Area (A) = πD²/4 where D = 16.0 cm = 0.16 m
A = 3.143×(0.16)²/4 = 0.02 m²
Also
a = πd²/4 where d = 2 cm = 0.02 cm
a = 3.143×(0.02)²/4
a = 0.0157 m²
Substituting these values into equation 2
f = (3200×0.0157)/0.02
f = 2512 N
The force applied to the smaller piston = 2512 N
