Respuesta :

r3t40

To find solutions you have to simplify disjunctives first.

[tex]

-9x+5\leq17\Longrightarrow x\leq-\frac{4}{3} \\

13x+25\leq-1\Longrightarrow x\leq-2 \\

[/tex]

Now write the simplified disjunctives as intervals

[tex]

x\in\Big(-\infty,-\frac{4}{3}\Big] \\

x\in(-\infty,-2]

[/tex]

Since the solution is a disjunction [tex]x\leq-\frac{4}{3}\vee x\leq-2[/tex] we can rewrite as union of intervals and simplify the union to get solution.

[tex]

\Big(-\infty,-\frac{4}{3}\Big]\cup(-\infty,-2]\Longrightarrow\boxed{(-\infty,-2]}

[/tex]

The answer is B.

Hope this helps.

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