Can somebody help me with this question?

To find solutions you have to simplify disjunctives first.
[tex]
-9x+5\leq17\Longrightarrow x\leq-\frac{4}{3} \\
13x+25\leq-1\Longrightarrow x\leq-2 \\
[/tex]
Now write the simplified disjunctives as intervals
[tex]
x\in\Big(-\infty,-\frac{4}{3}\Big] \\
x\in(-\infty,-2]
[/tex]
Since the solution is a disjunction [tex]x\leq-\frac{4}{3}\vee x\leq-2[/tex] we can rewrite as union of intervals and simplify the union to get solution.
[tex]
\Big(-\infty,-\frac{4}{3}\Big]\cup(-\infty,-2]\Longrightarrow\boxed{(-\infty,-2]}
[/tex]
The answer is B.
Hope this helps.