Time taken to fall tennis ball from height of 60 m is 6.35330 seconds
The three sets of approximation of time is: t ≈ 6.353 seconds and t ≈ 6.35 seconds and t ≈ 6.4 seconds
Solution:
Given that Tobias dropped a tennis ball from a height of 60 meters
The time in seconds it takes for the ball to fall 60 feet is given by:
[tex]0.25\sqrt{60} \text{ seconds }[/tex] ---- eqn 1
Let us calculate time taken to fall tennis ball from height of 1 feet
time taken to fall tennis ball from height of 1 feet = time taken to fall tennis ball from height of 60 feet divided by 60
So Divide eqn 1 by 60
[tex]\frac{0.25\sqrt{60}}{60} \text{ seconds }[/tex]
Since Tobias dropped a tennis ball from a height of 60 meters, let us convert 60 meters to foot
1 meter = 3.28084 foot
60 meter = 196.85 foot
Therefore, Time taken to fall tennis ball from height of 60 m is given as:
[tex]\rightarrow \frac{0.25\sqrt{60}}{60} \times 196.85 \\\\\rightarrow \frac{1.9364}{60} \times 196.85\\\\\rightarrow 0.03227 \times 196.85\\\\\rightarrow 6.35330[/tex]
Thus Time taken to fall tennis ball from height of 60 m is 6.35330 seconds
Finding three sets of approximations for the amount of time:
t = 6.35330 seconds
We can round to first three decimal places and then two decimal places and then one decimal place
First look at the digit to immediate right of rounding off digit
If that digit is less than 5, do not change the rounding digit but drop all digits to the right of it.
If that digit is greater than or equal to five, add one to the rounding digit and drop all digits to the right of it.
To the nearest thousandth:
t ≈ 6.353 seconds
To the nearest hundredth
t ≈ 6.35 seconds
To the nearest tenth
t ≈ 6.4 seconds