Answer:
sin(2A) = (2√2 + √3) / 6
Step-by-step explanation:
2A = (A+B) + (A−B)
sin(2A) = sin((A+B) + (A−B))
Angle sum formula:
sin(2A) = sin(A+B) cos(A−B) + sin(A−B) cos(A+B)
sin(2A) = 1/2 cos(A−B) + 1/3 cos(A+B)
Pythagorean identity:
sin(2A) = 1/2 √[1 − sin²(A−B)] + 1/3 √[1 − sin²(A+B)]
sin(2A) = 1/2 √(1 − 1/9) + 1/3 √(1 − 1/4)
sin(2A) = 1/2 √(8/9) + 1/3 √(3/4)
sin(2A) = 1/3 √2 + 1/6 √3
sin(2A) = (2√2 + √3) / 6
