Question

Find the value of the polynomial 2x^3y^3+3xy−3x^3y^3+x^2y−xy+2x^2y, for x=−1 and y=2.

Answer 1

Answer: 10

Step-by-step explanation:

2x³y³ + 3xy - 3x³y³ +x²y - xy + 2x²y, where x = -1 and y = 2

Now substitute  for x and y in the expression above.

2(-1)³(2)³ + 3(-1)(2)  - 3(-1)³(2)³ + (-1)²(2) - (-1)(2) + 2(-1)²(2)

(-2)(8)  + (-3)(2)  + 3(8)  +(1)(2)  +  (1)(2) + 2(1)(2)

= -16 -6  + 24  + 2 + 2 + 4

=  -22 + 32

=  10

Answer 2

Answer:

10

Step-by-step explanation:

common sense