Respuesta :
No, because if y is in fact 9 then the expression [tex]3y<27[/tex] evaluates to [tex]27<27[/tex] which is a false hence y cannot be 9 but rather [tex]y\in(-\infty,9)[/tex].
Hope this helps.
Answer: No
Step 1: Rewrite the equation
3y<27
Step 2: Get y alone
To do this we need to divide both 3y and 27 by 3
3y<27
3y/3<27/3
y=9
Step 3: Substitution
We now know that y equals 9. Now let’s substitute this into the equation
3y<27
3(9)<27
27<27
Step 4: Determining the answer
Since 27 is not less than (27), 9 is not the solution for y. However, any number less than 9 would work for this equation
Hope this helps comment below for more questions :)
Step 1: Rewrite the equation
3y<27
Step 2: Get y alone
To do this we need to divide both 3y and 27 by 3
3y<27
3y/3<27/3
y=9
Step 3: Substitution
We now know that y equals 9. Now let’s substitute this into the equation
3y<27
3(9)<27
27<27
Step 4: Determining the answer
Since 27 is not less than (27), 9 is not the solution for y. However, any number less than 9 would work for this equation
Hope this helps comment below for more questions :)