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  • 29-12-2019
  • Mathematics
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find maclaurin series for e^(-x)​

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r3t40
r3t40 r3t40
  • 29-12-2019

Maclaurin series for this function is

[tex]1-x+\frac{1}{2}x^2-\frac{1}{6}x^3+\frac{1}{24}x^4+\cdots=e^{-x}[/tex]

Hope this helps.

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