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A sound wave traveling through a certain freshwater lake has a frequency of 349.2 Hz and a wavelength of 4.25 m. What is the speed of a sound wave in this water? (Round your answer to three significant figures.)

Respuesta :

Answer:

ν = 1483.939 m/s

Explanation:

Wave propagation speed (ν):

  • ν = λ / T

∴ Wavelength ( λ ) = 4.25 m

∴ Period ( T ) = 1 / f

∴ frequency ( f ) = 349.2 Hz ( s-1 )

⇒ T = 1 / 349.2 s-1

⇒ T = 2.864 E-3 s

⇒ ν = (4.25 m) / (2.864 E-3 s)

⇒ ν = 1483.939 m/s

Answer: The wave speed of the given sound wave is [tex]1.48\times 10^3m/s[/tex]  

Explanation:

Wave speed is defined as the product of its wavelength and frequency.

Mathematically,

[tex]\text{Wave speed}=\lambda\times \nu[/tex]

where,

[tex]\lambda [/tex] = wavelength of the wave = 4.25 m

[tex]\nu [/tex] = frequency of the wave = 349.2 Hz = [tex]349.2s^{-1}[/tex]

Putting values in above equation, we get:

[tex]\text{Wave speed}=4.25m\times 349.2s^{-1}\\\\\text{Wave speed}=1484.1m/s=1.48\times 10^3m/s[/tex]

Hence, the wave speed of the given sound wave is [tex]1.48\times 10^3m/s[/tex]

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