Question

A rectangle has a height of 4a^2 and a width of 6a^2+9a+3.

Express the area of the entire rectangle.

Answer 1

Answer:

24a^4 +36a^3+12a^2

Step-by-step explanation:

area = height × width

area= 4a^2(6a^2+9a+3)

area = 24a^4 +36a^3+12a^2

Answer 2

The area of the entire rectangle can be expressed as $4a^2\times(6a^2+9a+3)=24a^4+36a^3+12a^2$

What is a rectangle?

A rectangle is a two-dimensional shape with four sides and four corners in geometry. Its two sides are at a right angled to each other. As a result, a rectangle has four angles, each measuring 90 degrees. The lengths of the opposite sides of a rectangle are equal and parallel.

How to find the area of a rectangle?

The area of a rectangle is the product of its two adjacent sides. i.e. If 'h' and 'w' be the height and width of a rectangle respectively, then the area of the given rectangle can be given by

area of the rectangle = height × width = h × w = hw

How to solve the problem?

The area of the entire rectangle is

$hw=4a^2\times(6a^2+9a+3)=24a^4+36a^3+12a^2$

Therefore, the area of the entire rectangle is given by $24x^4+36x^3+12x^2$

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