CHCK Farms raises hens and roosters. They have enough space to raise at most 300 birds per year. Each hen eats 80 pounds of food per year, and each rooster eats 60 pounds of food per year. The business can only afford 20,000 pounds of food per year. The graph below shows the solution set of a system of linear inequalities that represents this situation.

Respuesta :

Answer:

The number of hens is 100 and the number of roosters is 200.

Step-by-step explanation:

Let the number of hens be x and the number of roosters be y

then the total number of  hens and roosters, is 300

so,

[tex]x+y \leq 300[/tex]----------------------------(1)

Also  the hen eats 80 pounds of food per year and roosters eats 60 pounds of food per year,

[tex]80x+60y \leq 20000[/tex]----------------(2)

To solve the equations , multilpy eq(1) by 80

[tex]80x+80y \leq 24000[/tex]------------------(3)

Subracting (2) from (3)

[tex]20y \leq 4000[/tex]

[tex]y \leq 200[/tex]

substituting y in eq(1) we get

[tex]x+200 \leq 300[/tex]

[tex] x \leq 300-200[/tex]

[tex] x \leq 100[/tex]

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